10^2+24^2=c^2

Solution for 10^2+24^2=c^2 equation:

10^2+24^2=c^2

We move all terms to the left:

10^2+24^2-(c^2)=0

We add all the numbers together, and all the variables

-1c^2+676=0

a = -1; b = 0; c = +676;
Δ = b2-4ac
Δ = 02-4·(-1)·676
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-52}{2*-1}=\frac{-52}{-2}
=+26
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+52}{2*-1}=\frac{52}{-2}
=-26
$